Question #201800

An electrical load operates at 240 V rms The load absorbs an average of 8 Kw at lagging power factor of 0.9 The load impedance is:


 Select one:

 A 5.04 L 45 57 °Ω

 B 3.6 L 60 °Ω

 C 5.76 L 36.87 °Ω

 D 4.32 L 53.13 °Ω

 E 6.48 L 25.84 °Ω


1
Expert's answer
2021-06-04T05:08:02-0400

Average power, P =8KW= 8KW

But P=/S/cosθP=/S/ cos \theta

Given power factor cosθ=0.9cos \theta=0.9

=sinθ=1cos2θ=sin \theta=\sqrt{1-cos^2\theta}

=sinθ=10.92=0.19=0.44=sin \theta=\sqrt{1-0.9^2}=\sqrt{0.19}=0.44

P=/S/cosθP=/S/ cos \theta

8KW=/S/0.98KW=/S/*0.9

/S/=80000.9=8888.89/S/=\frac{8000}{0.9}=8888.89

Reactive power, Q =/S/sinθ=/S/ sin\theta VAR

Q=8888.89(0.44)=3910.72Q=8888.89(0.44)=3910.72 VAR

S=P+jQS=P+jQ

S=8000+j3910.72S=8000+j3910.72

S=8+j3.91S=8+j3.91 KVA

Impedence, Z SI2=4.3253.13°Ω\frac{S}{I^2}=4.32 \angle 53.13 °Ω


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