Average power, P =8KW
But P=/S/cosθ
Given power factor cosθ=0.9
=sinθ=1−cos2θ
=sinθ=1−0.92=0.19=0.44
P=/S/cosθ
8KW=/S/∗0.9
/S/=0.98000=8888.89
Reactive power, Q =/S/sinθ VAR
Q=8888.89(0.44)=3910.72 VAR
S=P+jQ
S=8000+j3910.72
S=8+j3.91 KVA
Impedence, Z I2S=4.32∠53.13°Ω
Comments