An electrical load operates at 240 V rms The load absorbs an average of 8 Kw at lagging power factor of 0.9 The load impedance is:
Select one:
A 5.04 L 45 57 °Ω
B 3.6 L 60 °Ω
C 5.76 L 36.87 °Ω
D 4.32 L 53.13 °Ω
E 6.48 L 25.84 °Ω
Average power, P =8KW= 8KW=8KW
But P=/S/cosθP=/S/ cos \thetaP=/S/cosθ
Given power factor cosθ=0.9cos \theta=0.9cosθ=0.9
=sinθ=1−cos2θ=sin \theta=\sqrt{1-cos^2\theta}=sinθ=1−cos2θ
=sinθ=1−0.92=0.19=0.44=sin \theta=\sqrt{1-0.9^2}=\sqrt{0.19}=0.44=sinθ=1−0.92=0.19=0.44
P=/S/cosθP=/S/ cos \thetaP=/S/cosθ
8KW=/S/∗0.98KW=/S/*0.98KW=/S/∗0.9
/S/=80000.9=8888.89/S/=\frac{8000}{0.9}=8888.89/S/=0.98000=8888.89
Reactive power, Q =/S/sinθ=/S/ sin\theta=/S/sinθ VAR
Q=8888.89(0.44)=3910.72Q=8888.89(0.44)=3910.72Q=8888.89(0.44)=3910.72 VAR
S=P+jQS=P+jQS=P+jQ
S=8000+j3910.72S=8000+j3910.72S=8000+j3910.72
S=8+j3.91S=8+j3.91S=8+j3.91 KVA
Impedence, Z SI2=4.32∠53.13°Ω\frac{S}{I^2}=4.32 \angle 53.13 °ΩI2S=4.32∠53.13°Ω
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