Question #201796

An electrical load operates at 240 V rms. The load absorbs an average of 5 KW at lagging power factor of 0.8 The reactive power Q is:


 Select one

 a 3.75 KVAR

 b 4.50 KVAR

 c 6.00 KVAR

 d 6.75 KVAR

 e 5.25 KVAR


1
Expert's answer
2021-06-03T16:22:02-0400

Average power, P =5KW= 5KW

But P=/S/cosθP=/S/ cos \theta

Given power factor cosθ=0.8cos \theta=0.8

=sinθ=1cos2θ=sin \theta=\sqrt{1-cos^2\theta}

=sinθ=10.82=0.36=0.6=sin \theta=\sqrt{1-0.8^2}=\sqrt{0.36=0.6}

P=/S/cosθP=/S/ cos \theta

5KW=/S/0.85KW=/S/*0.8

/S/=50000.8=6250/S/=\frac{5000}{0.8}=6250

Reactive power, Q =/S/sinθ=/S/ sin\theta VAR

Q=6250(0.6)=3750Q=6250(0.6)=3750 VAR

S=P+jQS=P+jQ

S=5000+j3750S=5000+j3750

S=5+j3.75S=5+j3.75 KVA


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