Question #200353

Design an operational amplifier circuit to form the weighted sum V0 = – (2V1+V2).


1
Expert's answer
2021-05-31T06:22:01-0400

Assume : Op-amp is ideal, so the virtual ground is applicable

V+V^+ (non inverting) = VV^- (Inverting)=0

By KCL at (Inverting terminal)

V1R1+V2R2=0Vout2K\frac{V_1}{R_1}+\frac{V_2}{R_2}=\frac{0-V_{out}}{2K}

So, Vout=2K[V1R1+V2R2]=[V1R12K+V2R22K]V_{out}=-2K[\frac{V_1}{R_1}+\frac{V_2}{R_2}]=-[\frac{V_1}{\frac{R_1}{2K}}+\frac{V_2}{\frac{R_2}{2K}}] .........(1)

Now comparing with given equation

Vout=[V112+V212]V_{out}=-[\frac{V_1}{\frac{1}{2}}+\frac{V_2}{\frac{1}{2}}] .....................(2)

Comparing 1 and 2

R12K=12;R12K=2    R1=1KΩ;R2=4KΩ\frac{R_1}{2K}=\frac{1}{2}; \frac{R_1}{2K}=2 \implies R_1=1K \Omega; R_2=4K \Omega


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