A 10mV, 2KHz sinusoidal signal is applied to the input of an op-amp integrator for which R=100 kΩ and C=1 μF. Find the output voltage.
Vo=−1RC∫vidtV_o=-\frac{1}{RC}\int v_idtVo=−RC1∫vidt
vin=vmsinωt=10sin2πft=10sin4000πt mVv_{in}= v_msin \omega t=10 sin 2\pi ft=10 sin4000 \pi t \space mVvin=vmsinωt=10sin2πft=10sin4000πt mV
So, −1100∗103∗1∗10−6∫10sin4000πtdt mV=0.025πcos4000πt mV\frac{-1}{100*10^3*1*10^{-6}}\int 10 sin 4000 \pi tdt \space mV = \frac{0.025}{\pi}cos 4000 \pi t \space \space mV100∗103∗1∗10−6−1∫10sin4000πtdt mV=π0.025cos4000πt mV
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