A 228V constant potential generator delivers load to a variable impedance whose values of R and X
are readily adjustable. Assuming a looking-back impedance of (6+j4.5) ohms calculate, for maximum
power,
a. The load impedance
b. The current
c. Load power
d. power factor
a) For maximum power transfer the load impedance "=6-j4.5"
b) The current "=228\/12= 19A"
c) The load power"=I^2R=19^2\\times6=2166W"
d) The load power factor is "Cos(tan^{-1}(4.5\/6) )=cos36.86\\degree=0.8lead"
Comments
In solving current, how you arrivedget that 12 as your resistance?
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