Question #200323

A 228V constant potential generator delivers load to a variable impedance whose values of R and X 

are readily adjustable. Assuming a looking-back impedance of (6+j4.5) ohms calculate, for maximum 

power,

a. The load impedance

b. The current

c. Load power

d. power factor


1
Expert's answer
2021-05-31T06:21:55-0400

a) For maximum power transfer the load impedance =6j4.5=6-j4.5


b) The current =228/12=19A=228/12= 19A


c) The load power=I2R=192×6=2166W=I^2R=19^2\times6=2166W


d) The load power factor is Cos(tan1(4.5/6))=cos36.86°=0.8leadCos(tan^{-1}(4.5/6) )=cos36.86\degree=0.8lead

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Comments

Hatdok
31.05.21, 13:40

In solving current, how you arrivedget that 12 as your resistance?

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