Answer to Question #199856 in Electrical Engineering for lucky

Question

 A series R L circuit is connected to a 110V ac source. If the voltage across the resistor is 85 V, find the power dissipated in the circuit

Answer 1

$P_{avr}=\frac{1}{2}I_0U_R=\frac{1}{2}\frac{U_R^2}{R}$

Assume that $R=20\ \Omega$ . So, we have

$P_{avr}=\frac{1}{2}\frac{U_R^2}{R}=\frac{1}{2}\frac{85^2}{20}=180.6\ (W)$ . Answer