Answer to Question #198426 in Electrical Engineering for abcd

Question #198426

If an amplifier working with ±5 V DC power supplies requires a minimum output voltage of 2.3 V across a load resistance of 185 ohms, calculate the minimum average current to be drawn from each power supply, if the efficiency of the amplifier is 50 %.


1
Expert's answer
2021-05-26T15:34:02-0400

Efficiency , η=50\eta=50% %=0.50=0.50

Pout=Vout2R=2.32185=0.02859_{out}=\frac{V^2_{out}}{R}=\frac{2.3^2}{185}=0.02859

η=PoutPdc=0.50=0.02859Pdc\eta=\frac{P_{out}}{P_{dc}}=0.50=\frac{0.02859}{P_{dc}}

Pdc=0.028590.5=0.057189P_{dc}=\frac{0.02859}{0.5}=0.057189

VccIc=PdcV_{cc}I_{c}=P_{dc}

Ic=PdcVcc=0.0571895=0.0114378AI_c=\frac{P_{dc}}{V{cc}}=\frac{0.057189}{5}=0.0114378A


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