Answer to Question #198426 in Electrical Engineering for abcd

Question

If an amplifier working with ±5 V DC power supplies requires a minimum output voltage of 2.3 V across a load resistance of 185 ohms, calculate the minimum average current to be drawn from each power supply, if the efficiency of the amplifier is 50 %.

Answer 1

Efficiency , $\eta=50$ %$=0.50$

P$_{out}=\frac{V^2_{out}}{R}=\frac{2.3^2}{185}=0.02859$

$\eta=\frac{P_{out}}{P_{dc}}=0.50=\frac{0.02859}{P_{dc}}$

$P_{dc}=\frac{0.02859}{0.5}=0.057189$

$V_{cc}I_{c}=P_{dc}$

$I_c=\frac{P_{dc}}{V{cc}}=\frac{0.057189}{5}=0.0114378A$