Question

Calculate the mutual inductance between two coils that are inductively coupled if 112V is induced in the secondary when the 60-cylce primary current is 2.8 Amp.

Answer 1

$i=i_0\sin\omega t$

$E_2=-M_{21}\frac{di}{dt}=-M_{21}i_0\omega\cdot\cos\omega t$ . So,

$M_{21}=E_2/(i_0\omega)=112/(2.3\cdot2\cdot3.14\cdot60)=0.297\ (H)$