Calculate the mutual inductance between two coils that are inductively coupled if 112V is induced in the secondary when the 60-cylce primary current is 2.8 Amp.
"i=i_0\\sin\\omega t"
"E_2=-M_{21}\\frac{di}{dt}=-M_{21}i_0\\omega\\cdot\\cos\\omega t" . So,
"M_{21}=E_2\/(i_0\\omega)=112\/(2.3\\cdot2\\cdot3.14\\cdot60)=0.297\\ (H)"
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