onsider the single stage amplifier, values of h-parameters are hie=X1.X2 kΩ, hfe=(150-X1), hre=X1. X2˟10-4 and hoe=50µA/V. Rs=X1X2 Ω, Calculate Av, Ai, Ri, Zo
Av=hfehrehfe−hve(Rs+hie)=1491.3×10−4×149−50×10−6×(0.013+1.3)Av=\dfrac{h_{f_e}}{h_{re}h_{fe}-h_{ve}(R_s+h_{ie})} \\[9pt] =\dfrac{149}{1.3\times 10^{-4}\times 149-50\times 10^{-6}\times (0.013+1.3)}Av=hrehfe−hve(Rs+hie)hfe=1.3×10−4×149−50×10−6×(0.013+1.3)149
Av=7718.46
Ai=−hfe=−149Ai=-h_{fe}=-149Ai=−hfe=−149
As we know ,
Rin=hie−hfehrehoe=1.3−149×1.3×10−450×10−6R_{in}=h_{ie}-\dfrac{h_{fe}h_{re}}{h_{oe}} \\[9pt] =1.3-\dfrac{149\times 1.3\times 10^{-4}}{50\times 10^{-6}}Rin=hie−hoehfehre=1.3−50×10−6149×1.3×10−4
Rin=0.912KΩR_{in}=0.912 K\OmegaRin=0.912KΩ
Zo=1hoe−hfehreRs+hieZ_o=\dfrac{1}{h_{oe}-\frac{h_{fe}h_{re}}{R_s+h_{ie}}}Zo=hoe−Rs+hiehfehre1
=150×10−6−1.49×1.3×10−40.013+1.3×103=28.489KΩ=\dfrac{1}{50\times 10^{-6}-\frac{1.49\times 1.3\times 10^{-4}}{0.013+1.3\times 10^3}} \\[9pt] =28.489K\Omega=50×10−6−0.013+1.3×1031.49×1.3×10−41=28.489KΩ
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