Question #183581

A capacitor consists of two similar square aluminium plates, each 10 cm × 10 cm mounted parallel and opposite to each other. What is their capacitance in μ F when distance between them is 1 cm and the dielectric is air


1
Expert's answer
2021-04-21T07:04:01-0400

The capacity of a flat capacitor is C=ϵϵ0SdC=\cfrac{\epsilon \cdot\epsilon_0 \cdot S}{d}

Where

ϵ=1\epsilon=1

ϵ0=8.851012Fm\epsilon_0=8.85 \cdot 10^{-12} \cfrac{F}{m}

S=0.10.1m2=1102m2S=0.1 \cdot 0.1 m^2=1 \cdot 10^{-2} m^2

d=1102md=1 \cdot 10^{-2} m

Then

C=18.85101211021102=8.851012F=0.00885μFC=\cfrac{1 \cdot8.85 \cdot 10^{-12} \cdot 1 \cdot 10^{-2}}{1 \cdot 10^{-2}}=8.85 \cdot 10^{-12}F=0.00885\mu F


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