A capacitor consists of two similar square aluminium plates, each 10 cm × 10 cm mounted parallel and opposite to each other. What is their capacitance in μ F when distance between them is 1 cm and the dielectric is air
The capacity of a flat capacitor is C=ϵ⋅ϵ0⋅SdC=\cfrac{\epsilon \cdot\epsilon_0 \cdot S}{d}C=dϵ⋅ϵ0⋅S
Where
ϵ=1\epsilon=1ϵ=1
ϵ0=8.85⋅10−12Fm\epsilon_0=8.85 \cdot 10^{-12} \cfrac{F}{m}ϵ0=8.85⋅10−12mF
S=0.1⋅0.1m2=1⋅10−2m2S=0.1 \cdot 0.1 m^2=1 \cdot 10^{-2} m^2S=0.1⋅0.1m2=1⋅10−2m2
d=1⋅10−2md=1 \cdot 10^{-2} md=1⋅10−2m
Then
C=1⋅8.85⋅10−12⋅1⋅10−21⋅10−2=8.85⋅10−12F=0.00885μFC=\cfrac{1 \cdot8.85 \cdot 10^{-12} \cdot 1 \cdot 10^{-2}}{1 \cdot 10^{-2}}=8.85 \cdot 10^{-12}F=0.00885\mu FC=1⋅10−21⋅8.85⋅10−12⋅1⋅10−2=8.85⋅10−12F=0.00885μF
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