Answer to Question #178534 in Electrical Engineering for Aren Benjamin

Question

The voltage applied to a purely inductive coil of self inductance 16.5mh is given by the equation v=150sin314t+125sin942t+100sin1570t

Answer 1

As we see, this voltage has higher harmonics. third and fifth harmonics are present. How do we know? Divide frequency of the second and third term by the frequency of the first term:

$$h_3=\frac{942}{314}=3,\\\space\\ h_5=\frac{1570}{314}=5.$$