Answer to Question #178534 in Electrical Engineering for Aren Benjamin

Question #178534

The voltage applied to a purely inductive coil of self inductance 16.5mh is given by the equation v=150sin314t+125sin942t+100sin1570t


1
Expert's answer
2021-04-12T01:55:54-0400

As we see, this voltage has higher harmonics. third and fifth harmonics are present. How do we know? Divide frequency of the second and third term by the frequency of the first term:


"h_3=\\frac{942}{314}=3,\\\\\\space\\\\\nh_5=\\frac{1570}{314}=5."



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