V=10 sin 2π100t
Let the velocity of the body change according to the law v=10sin(2π100t)v=10\sin(2\pi100t)v=10sin(2π100t) . How its acceleration changes?
a=dvdt=10cos(2π100t)⋅2π100=2000πcos(2π100t)a=\frac{dv}{dt}=10\cos(2\pi100t)\cdot2\pi100=2000\pi\cos(2\pi100t)a=dtdv=10cos(2π100t)⋅2π100=2000πcos(2π100t)
amax=2000πa_{max}=2000\piamax=2000π
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