Consider a circuit with 5 inductors connected in parallel:

The voltage across each resistor will be the same (as they are in parallel) 230 V.
The reactance of the circuit:
X=(X1−1+X2−1+X3−1+X4−1+X5−1)−1,Xi=ωLi=2πfLi.For equal values of X, we have
X=5XL=52πfL=628.3 kΩ.The current in each resistor is
IL=XLV=628300230=366⋅10−6 A. The reactance of a single inductance at 500 Hz will be
XL500=2πf500L=1570 Ω.
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