Question #170648

A coil with resistance ‘

6

’

Ω

,

and

inductance

‘

8

’ mH

is connected

in parallel

with a

series

combination of

a

resist

or and

capacitor

having

resistance R

Ω and

reactance X

c

Ω.

If

t

he equivalent

impedance

of the resulting circuit is

Z =

5

/0

o

Ω at

ω

=1000 rad/sec

. Find the

values of R & C

.



Expert's answer

Given, ZL=6+j8Z_L = 6+j8


It is connected across R−jXR-jX


The resultant parallel combination yields

5∠05\angle0 .


i. e(6+j8)(R−jX)(6+R)+j(8−X)=5+j0\frac{(6+j8) (R-jX) }{(6+R) +j(8-X)} =5+j0


Simplifying and equating real and imaginary parts, we have,


R+8X=308R−X=40R+8X=30 \newline 8R-X=40


Solving we have

R=5.38ΩX=3.077ΩAlsoZ=5.38−j3.07R= 5.38\Omega\newline X=3.077\Omega \newline Also Z = 5.38-j3.07


Also X=1/Cω  ⟹  C=0.325μFX=1/C\omega\implies C=0.325\mu F


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