Question #167442

Draw the phasor diagram and find the sum of the currents i1=141.42sin(wt+90),i2=-70 71ciswt,i3=50e^j60,i4=100(-120),i5=50(cos60+jsin60)



Expert's answer

the sum of the currents=sin(wt+90),i2


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Canada #340153 on Dec 2023