If the currents in the three parallel branches of an ac circuit are given as I1 =
2530A, I2 = 25e-jΠ/6A and I3 = (50 + j 50)A, express the total current in the form
(i) I Φ and (ii) Im sin (ωt + Φ)
1) I=105.85<28.180I = 105.85 \text{\textless} 28.18^0I=105.85<28.180
2) 105.85=(wt+118.18)105.85 = (wt+118.18)105.85=(wt+118.18)
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