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Answer to Question #165822 in Electrical Engineering for Enthada Nokkunne
Question #165822
Draw the phasor diagram and find the sum of the currents: i1=141.42 Sin(ωt + /2) , i2 = -70.71 Cosωt , i3= 50 e^jπ/3 , i4=100 -2π/3 and i5= 50 (Cos π/3 + j Sinπ/3)
Expert's answer
sum of the currents=42 Sin(ωt + /2)+100 -2π/3
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