Answer to Question #165822 in Electrical Engineering for Enthada Nokkunne

Question

Draw the phasor diagram and find the sum of the currents: i1=141.42 Sin(ωt + /2) , i2 = -70.71 Cosωt , i3= 50 e^jπ/3 , i4=100 -2π/3 and i5= 50 (Cos π/3 + j Sinπ/3) 

Answer 1

sum of the currents=42 Sin(ωt + /2)+100 -2π/3