Answer to Question #158576 in Electrical Engineering for kyle

Question

1.  An activated sludge system has a flow of 4000 m³/day with X = 4000 mg/L and S₀ = 300 mg/L. From pilot plant work the kinetic constants are Y =0.5, μˆ =3 d−1, K_S =200 mg/L. We need to design an aeration system that will remove 90% of the BOD5. Specifically, we need to know (a) the volume of the aeration tank; (b) the sludge age; (c) the amount of waste activated sludge.

Answer 1

a)= Volume of the aeration tank = 346.2 m³

b)= Q_c = 2,55 days

c)- The amount of sludge waste = 339.3 log/day