Input voltage (rms value) =120V=120V=120V
Load resistance value =10Ω=10\varOmega=10Ω
a) Average voltage output is given
Vo=Vmπ=120×2π=54.02VV_o = \frac{V_m}{\pi}= \frac{120\times \sqrt{2}}{\pi} = 54.02VVo=πVm=π120×2=54.02V
Average load current is given by
Io=VoR=54.0210=5.4AI_o = \frac{V_o}{R} =\frac{54.02}{10}=5.4AIo=RVo=1054.02=5.4A
b) Effective voltage or rms voltage output
Vr=Vm2=120×22=84.85VV_r = \frac{V_m}{2}=\frac{120\times\sqrt{2}}{2}=84.85VVr=2Vm=2120×2=84.85V
Effective output current
Ir=VrR=84.8510=8.5AI_r =\frac{V_r}{R}=\frac{84.85}{10}=8.5AIr=RVr=1084.85=8.5A
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