If an R = 1-kΩ resistor, a C = 1-µF capacitor, and an L = 0.2-H inductor are connected in
series with a V = 150 sin (377t) volts source, what is the maximum current delivered by the source?
1
Expert's answer
2020-11-09T14:18:53-0500
Solution: Based on the datas given in the question a circuit diagram can be constructed as shown in the below figure.
From this we can calculate capacitive reactance = Xc=1/Cω=1/(10−6×377)=2652.52Ω
The inductive reactance =
XL=Lω=0.2×377=75.4Ω.
The rms value of input voltage =150/2=106.07V
Hence an equivalent circuit in the frequency domain incorporating the sign of capacitive and inductive reactance is as shown below
Total impedance of the circuit = ZT=R+j(XL−Xc)=1000+j(75−2652.52)
ZT=1000+j2577.12Ω
Current through the circuit = V/ZT=106.07/(1000−j2577.12)=0.01388+j0.03577
There for current I=0.03837∠68.79°
We obsereve the rms value = 38.37mA
Maximum value of current = rmsvalue×2=38.37×2=54.26mA
The current can be written in sinusoidal form as 54.26Sin(377t+68.79°)mA
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