Base on the data given in the question a circuit could be constructed as shown,
The phasor diagram for a RLC Series circuit could be drawn as follows,
Comparing the phasor diagram and given information following datas are given,
VR=15V
VL=22V
VS=48V
From the phasor diagram (VC−VL)=(VS2−VR2)21=(482−152)21=45.6V
There fore Vc=(VC−VL)+VL=45.6+22=67.6V
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