If 12 is the voltage and the frequency is standard 50 Hz, the magnitude of a current will be
"I=\\frac{V}{Z}."Find the impedance:
"Z=\\sqrt{R^2+(X_L-X_C)^2}=\\\\\\space\\\\=\\sqrt{R^2+\\bigg(\\omega L-\\frac{1}{\\omega C}\\bigg)^2},\\\\\\space\\\\\nI=\\frac{V}{\\sqrt{R^2+\\bigg(\\omega L-\\frac{1}{\\omega C}\\bigg)^2}}=0.019\\text{ A}."
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