Answer to Question #120805 in Electrical Engineering for Nana Safo Boama

Question

A silicon pn-junction at T= 300k has a reverse-saturation current of IS=10^16A determine the forward bias diode current for VD=0.55V

Answer 1

I_D = (10^-16) [e^(0.55/0.026)-1]

= (10^-16) [1.53814*10⁹]

= 0.154*10^-6

= 0.154uA

Therefore the forward -bias current for V_D = 0.55v is I_D = 0.154uA