Question #115855

Two Electric field vectors E1 and E2 are perpendicular to each other; obtain its base

vectors.

Expert's answer

Imagine that these two vectors make up a resulting vector E θ degrees above i-axis, therefore, we can write that


E⃗=∣E∣cosθi+∣E∣sinθj.\vec{E}=|E|\text{cos}\theta \textbf{i}+|E|\text{sin}\theta \textbf{j}.

Now put that


a=∣E2∣∣E∣cosθ, b=∣E1∣∣E∣sinθ.a=\frac{|E_2|}{|E|\text{cos}\theta},\space b=\frac{|E_1|}{|E|\text{sin}\theta}.

Thus,


E⃗=a∣E2∣i+b∣E1∣j.\vec{E}=a|E_2|\textbf{i}+b|E_1|\textbf{j}.

Now the vector E can be written as a linear combination of E1⃗,E2⃗.\vec{E_1},\vec{E_2}. The basis vector is


<E1⃗,E2⃗>.<\vec{E_1},\vec{E_2}>.


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