Assume that the voltage source produces the voltage of RMS value of 220 V and frequency 50 Hz. The reactances of the inductance and capacitance are
"X_L=2\\pi fL,\\\\\nX_C=\\frac{1}{2\\pi fC}."Since this is a parallel connection, apply Ohm's law to each element to find current:
"I_R=\\frac{V}{R}=\\frac{220}{6}=36.7\\text{ A}.\n\\\\\nI_L=\\frac{V}{X_L}=\\frac{220}{2\\pi\\cdot50\\cdot7}=0.1\\text{ A}.\n\\\\\nI_C=\\frac{V}{X_C}=\\frac{220\\cdot42}{2\\pi\\cdot 50}=29.4\\text{ A}." The source current is
"I_s=\\sqrt{I_R^2+(I_L-I_C)^2}=22\\text{ A}."
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