Assume that the voltage source produces the voltage of RMS value of 220 V and frequency 50 Hz. The reactances of the inductance and capacitance are
XL=2πfL,XC=2πfC1.Since this is a parallel connection, apply Ohm's law to each element to find current:
IR=RV=6220=36.7 A.IL=XLV=2π⋅50⋅7220=0.1 A.IC=XCV=2π⋅50220⋅42=29.4 A. The source current is
Is=IR2+(IL−IC)2=22 A.
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