Resistivity of various materials:
ρ=RAl\rho=R\frac{A}{l}ρ=RlA
A - area in circular mils (CM)
l - length (feet)
R=0.5kΩ=500Ω−resistanceR=0.5k\Omega=500\Omega - resistanceR=0.5kΩ=500Ω−resistance
ρ=50094CM1000ft=47 CM⋅Ω/ft at 20°C\rho=500\frac{94CM}{1000ft}=47 ~CM\cdot \Omega/ft ~at~ 20°Cρ=5001000ft94CM=47 CM⋅Ω/ft at 20°C
the resulting resistivity value matches Nickel
Answer: Nickel
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