If we deal with Stirling cycle, we can convert and write temperatures:
"T_1=T_4=290\\text{ K},\\\\\nT_2=T_3=580\\text{ K}."
Efficiency:
"\\frac{p_3}{T_3}=\\frac{p_4}{T_4},\\\\\n\\space\\\\\np_3=\\frac{T_3}{T_4}p_4=580\/290\\cdot1.04=2.08\\text{ bar}."
Work ratio:
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