If we deal with Stirling cycle, we can convert and write temperatures:
T1=T4=290 K,T2=T3=580 K.
Efficiency:
η=1−T2T1=1−580290=0.5.T2p2=T1p1, p1=T2T1p2=290/580⋅62.4=31.2 bar.
T3p3=T4p4, p3=T4T3p4=580/290⋅1.04=2.08 bar.
Work ratio:
rw=Q23Q41=RT2 ln(p1/p4)RT1 ln(p2/p3)=0.5
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