Answer to Question #316150 in Civil and Environmental Engineering for Chaddwick

Question

AGGREGATE MOISTURE (ASTM C566)

MOISTURE CONTENT

DATA AND TABULATION

Mass of Container, Mc = _______35____g.

Mass of Container + original sample, Mc+w = ______520___g.

Mass of container + dried sample, Mc+D = ____472______g.

Mass of original sample, W = _______g.

Mass of Dried sample, D = ________g.

Answer 1

Mass of original sample, W = (Mass of Container + original sample, Mc+w) - Mass of Container, Mc

W = (Mc+w) - Mc

W = 520 g - 35 g

W = 485 g

Mass of Dried sample, D = (Mass of container + dried sample, Mc+D) - Mass of Container, Mc

D = (Mc+D) - Mc

D = 472 g - 35 g

D = 437 g