Question

An open cylindrical tank 4 ft in diameter and 6 ft deep is filled with water and rotated about it's axis at 60 rpm. How much liquid is spilled, and how deep is the water at the axis?

Answer 1

Volume of Tank = πR²h

R = Diameter /2 = 4/2 = 2ft

h = 6ft

= πR²h

= π$\times$2²$\times$6

= 24π ft³

Let say it can be rotated its axis at an angle 60 rpm

Then Volume of water which will not spill = πR²hCos60

= 2πCos60

=-5.98