0.675kg of gas at 1.4 MN/m2 and 2800C is expanded to four times the original volume according to the law PV1.3 =C Determine:
(a) the original and final volume of the gas,
(b) the final pressure of the gas
(c) the final temperature of the gas
Take R=0.287Kj/kg K
m1 = 0.675 kg
p1 = 1.4 MN/m2
T1 = 280°C
R = 0.287 kJ/kg K,
v2 = 4 V1
p1v1 = mRT1
(a.) v1 = mRT1 / T1
v1= = 0.0077
V2= 4V1= 410-3 = 0.03m3
(b.) P1V1n = P2V2n
P2= P1[]n= 14 103kPa[]1.3 = 2.3103 kPa
(c.)
T2 =
T2 =
T2 = 363.499 - 280 = 83.5°C
T2 = 83.5°C
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