Question #304234

the pitch of a jackscrew shown in figure 2 is 0.3 cm and has a lever arm of 60 cm lenght. What force at the end of the lever arm will raise a load of 190kg if the efficiencyof the machine is 12%?


1
Expert's answer
2022-03-02T04:17:02-0500

The force, required to raise a load of mass m is:


F=mgAMA,F=\frac{mg}{AMA},


where AMA - actual mechanical advantage.


AMA=Ed2d1,AMA=E\frac{d_2}{d_1},


where E - the efficiency of the machine;

d1 - the pitch of a jackscrew;

d2 - the distance, that the input force moves to raise a load on the distance d1.


Distance dis equal to the length of complete circle with the radius r, that is equal to the lenght of the lever arm.

So,


F=mgd1E2πr=1909.80.0030.1223.140.6=F=\frac{mgd_1}{E\cdot 2\pi r}=\frac{190\cdot 9.8\cdot 0.003}{0.12\cdot 2\cdot 3.14\cdot 0.6}= 12.3 N.


Answer: 12.3 N.


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