Answer to Question #294849 in Civil and Environmental Engineering for Topher

Question

Consider the fission reaction 1

0n + 235

92U →

89

37Rb + 3 0

-1e + 3 1

0n + 144

58Ce

How much energy in kilojoules is released per gram of Uranium- 235?

Answer 1

To determine the E? value of a cell, we determine the anode and cathode half cell reactions and then calculate the E? by the help of the formula:

E ? ( cell ) = E? (cathode) - E? (anode)

The half-cell reactions are written as below:

Anode: Na(s) → Na+ (aq) + e- E? (anode) = -2.714V

Cathode: Fe2+ (aq) + 2e- → Fe(s) E? (cathode) = -0.409V

So, E? (cell) = -0.409 – (-2.714) = 2.305V