Find the area bounded by y = (11 - x)^3, the lines y=x and the x-axis. *
According to second theorem of Guldino, volume obtined by a rotation of a section bounded by a function f(x)
and the x-axis between a and b is :V=π∫abf2(x)dxV=\pi\int_a^bf^2(x)dxV=π∫abf2(x)dx
In our case, we have
V=π∫12e(2x)dx=π/2(e4−e1)V= \pi \int_1^2e^{(2x)}dx=\pi/2(e^4-e^1)V=π∫12e(2x)dx=π/2(e4−e1)
so it will be: Y=(11−x)3Y=(11-x)^3Y=(11−x)3
=(11−4)3=343=(11-4)^3=343=(11−4)3=343
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