Initial investment = 10,000,000
Annual Savings = 2,500,000
Study Period = 4 years
Salvage Value = 6,000,000
Calculating the IRR using the Trial and Error Method.
Let the MARR is 15%
Calculate the PW of the investment at MARR of 15%
PW=−10,000,000+2,500,000(P/A,15%,4)+6,000,000(P/F,15%,4)PW=−10,000,000+2,500,000(2.8550)+6,000,000(0.5718)=568,300
The PW is positive. So, increase the rate of interest to get negative PW.
Increase the MARR to 16% and calculate the PW.
PW=−10,000,000+2,500,000(P/A,16%,4)+6,000,000(P/F,16%,4)PW=−10,000,000+2,500,000(2.7982)+6,000,000(0.5523)=309,300
The PW is still positive. So, increase the rate of interest to get negative PW.
Increase the MARR to 18% and calculate the PW.
PW=−10,000,000+2,500,000(P/A,18%,4)+6,000,000(P/F,18%,4)PW=−10,000,000+2,500,000(2.6901)+6,000,000(0.5158)=−179,950
Now, use interpolation and calculate the IRR.
IRR=16%+[309,300–0÷309,300–(−179,950)]∗2%IRR=17.26%
The IRR is 17.26 (not using the % sing as the question is mentioning)
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