Question #241404

A closed right cylindrical tank with a height of 8 m and 3 m in diameter contains water to a depth of 5m. If the tank is laid in a horizontal position, find the depth of water.


1
Expert's answer
2021-09-25T11:43:42-0400

cos12θ=0.5/2.5cos\frac{1}{2}θ=0.5/2.5


θ=156.926θ=156.926^∘

α=360θ=360156.926α=360^∘−θ=360^∘−156.926^∘


α=203.074α=203.074^∘

Area of cross section:

Ab=1/2r2(αrad+sinθdeg)A_b=1/2r^2(α_{rad}+sinθ_{deg})

Ab=12.3ft2A_b=12.3 ft^2

Volume of water:


Vw=AbL=12.3(8)V_w=A_bL=12.3(8)

Vw=98.4V_w=98.4


Depth of water in vertical position:


Vw=πr2hVw=πr^2h

98.4=π(2.52)h98.4=π(2.5^2)h


h=5.01 ft  answerh=5.01\space ft \space\space answer


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