Answer to Question #241404 in Civil and Environmental Engineering for Mr. Lee

Question

A closed right cylindrical tank with a height of 8 m and 3 m in diameter contains water to a depth of 5m. If the tank is laid in a horizontal position, find the depth of water.

Answer 1

$cos\frac{1}{2}θ=0.5/2.5$

$θ=156.926^∘$

$α=360^∘−θ=360^∘−156.926^∘$

$α=203.074^∘$

Area of cross section:

$A_b=1/2r^2(α_{rad}+sinθ_{deg})$

$A_b=12.3 ft^2$

Volume of water:

$V_w=A_bL=12.3(8)$

$V_w=98.4$

Depth of water in vertical position:

$Vw=πr^2h$

$98.4=π(2.5^2)h$

$h=5.01\space ft \space\space answer$