𝑖=(1+𝑟/𝑚)m−1𝑖=(1+𝑟/𝑚)^m-1i=(1+r/m)m−1
𝑖=(1+0.12/4)4−1𝑖=(1+0.12/4)^4-1i=(1+0.12/4)4−1
i=0.125509i=0.125509i=0.125509
I=i×100I=i\times100I=i×100
I=12.5509%I=12.5509\%I=12.5509%
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