Answer to Question #231200 in Civil and Environmental Engineering for Alan Enrico V Tuib

Question

Compute for the distance between the theodolite and the subtense bar if the subtended angle observed is 1degree 24 minutes and 32 seconds.

Answer 1

Distance = $H= \frac{D}{2} \cot \frac{\alpha}{2}$

$\frac{\alpha}{2}= \frac{1^0+(\frac{24}{60})^0+(\frac{32}{60*60})^0}{2}=\frac{\frac{317}{225}}{2}=0.70444$

If D = 2 m

$H= \frac{2}{2} \cot 0.70444= 1.17659 m$