Question

calculate development length required to be provided for m25 concrete and fe415 steel of diameter phi for bar in tension zone and in compression zone

Answer 1

Development length under Tension:

stress in bar = 415 Mpa

Bond stress M25 = 1.44

Diameter = phi

l.d = $(415 * \Phi) / (4 * 1.44 * 1.6)$

l.d = $45.03\Phi$

Development Length under compression

l.d = $(415 * \Phi) / (4 * 1.44 * 1.25)$

l.d = 57.639$\Phi$