1. If the weight is descending freely, determine the tension in the cord both before and after a brake force P – 100 lb is applied. Neglect the thickness of brake.
Taking mass moment inertia
"\\sum M_o=I_o\\alpha \\implies200*2-F_B(3)=80lb"
"and F_B=f_s*N_B=f_s*(4p)"
"A_s=p=100lb\\implies F_B=80lb" and "\\alpha =13.33rad ^{-1}"
"\\sum f_y=0 \\implies F_B+200=T \\implies 280lb"
"T_i=F_Be^{t_i*Q}= T_i=80*e^{0.20*Q_1}"
"T_2=80*e^{0.20*Q_2}\\\\\nQ_2=Tan(71.6^0)\\\\\nQ_1=tan(-45^0)\\\\\n\\therefore T_1=146lb ; T_2=65.2lb"
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