Question

a simple supported beam of 8m pan carries the total load of 23kn/m includingof of ot self weight .use m30 and fe 415 design the beam .

Answer 1

Self-weight of footing

$P = 23 kN/m*8m = 184 kN\\ P_T= 1.2 *184 kN = 220.8 kN\\$

From the M30 and the Fe415 design the beam

$W_T=\frac{P_T}{A}\\ 120=\frac{220.8}{A} \implies A = 1.84 \\$

$Area = S^2 \implies (B)= \sqrt{1.84}= 1.35646$

The size chosen can be $1.5 m \times 1.5 m$

Therefore area $= 2.25m^2$

Pressure

$P= FA \\ P =496.8 N/m^2$