Question

Write a balanced equation for 106/46 Of (a,p) 109/47 Ag

Answer 1

$_{46}^{106}Pd(\alpha, P) _{47}^{109} Ag \\\\ _2^4 \alpha=_2^4 He \space Nuclei \space \& \space P=proton\\\\ _{46}^{106}Pd +_2^4 \alpha \to _{47}^{109} Ag +P$