A sample to be used for medical imaging is labeled with F-18, which has a half- life of 110 min. What percentage of the original activity in the sample remains after 300min?
1
Expert's answer
2021-07-14T05:48:52-0400
Let the final activity be x
"\\ln \\frac{x}{100}= -\\frac{0.693}{110}*300\\\\\n\\ln \\frac{x}{100}= -1.89\\\\\n\\ln x - \\ln 100 = -1.89\\\\\n\\ln x =2.715\\\\\nx= 15.10 \\%"
Comments
Leave a comment