Question

A solid shaft 100 mm in diameter is subjected simultaneously to an axial compressive force of 50 kN and to a torque that twist through an angle of 1.5

Answer 1

If we were to find the torque

If $G_{steel} = 85 GPa$ we can find the torque of the twist.

$\frac{T}{J}=\frac{G \theta}{L} \implies T= \frac{G \theta}{L}J\\ T= \frac{ 85*10^9*\frac{1.5\pi}{180}}{1}*\frac{\pi}{32}*0.1^4\\ T=21.84678 kNm$