Question

A flat bar 75 mm wide by 9 mm thick and 1.2 m long is subjected to end moments of 202.5 N.m. Compute the deflection of the beam at the midspan if E = 200 000 MPa.

Answer 1

Moment of inertia

$I= \frac{75*10^{-3}*(9*10^{-3})^3}{12}=4.5562*10^{-3}m^4\\ \delta = \frac{Ml^2}{8EI}\\ \delta = \frac{202.5*1.2^2}{8*200000*10^6*4.562*10^{-5}}\\ \delta =40*10^{-3}$