A 2kg block is pulled with uniform speed up a plane which makes 30° with the horizontal force of 15 N which is parallel to the plane. Find the coefficient of kinetic friction between the block and the plane
µk=fkNµk=mgsinα−mamgcosαµk=−tanα−agcosαµk=−tanα−Fmgcosαµk=−tan30−1529.8cos30µk=−−0.306349µk=0.306349µ_k = \frac{f_k}{ N}\\ µ_k= \frac{mg sin α − ma}{ mg cos α}\\ µ_k= - tan α − \frac{a}{ g cos α}\\ µ_k= -tan α − \frac{\frac{F}{ m}}{ g cos α}\\ µ_k= - tan30 − \frac{\frac{15}{ 2}}{ 9.8 cos 30}\\ µ_k= - -0.306349\\ µ_k= 0.306349µk=Nfkµk=mgcosαmgsinα−maµk=−tanα−gcosαaµk=−tanα−gcosαmFµk=−tan30−9.8cos30215µk=−−0.306349µk=0.306349
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