Question #214615
A man drives for 30 minutes at a speed of 25m/s, then stops for 10 minutes, and finally drives for 20 minutes at 36 m/s. Calculate (a) the total distance traveled and (b) the average speed
1
Expert's answer
2021-07-12T03:36:18-0400

Part a

He firstly travels for 30 mins at 25 m/s

i.e. he travels for 30×60=1800seconds30 \times 60 = 1800 seconds

The distance he travels will be 1800×25=45000m(45km)1800 \times 25 =45000 m (45 km)

His second set of travelling is for 20 minutes at 36 m/s

i.e. he travels for 20×60=1200seconds20 \times 60 = 1200 seconds

The distance he travels will be 1200×36=43200m(43.2km)1200 \times 36 = 43200 m (43.2 km)

The total distance he travels will be 45000+43200=88200m.45000 + 43200 = 88200 m.


Part b

This means his average speed as the overall journey took one hour is

S=DT=882003600=24.5m/sS= \frac{D}{T}= \frac{88200}{3600} = 24.5 m/s\\


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS