Answer to Question #214610 in Civil and Environmental Engineering for syra

Question

An automobile accelerates from rest at 1 ft/s

Answer 1

If we were to calculate the distance covered, the following will be the steps.

$First \space distance \\ v=u+at \\ v=0+30*1\\ v=30ft/s\\ Distance, s= ut+\frac{1}{2}at^2=0.5*900= 450 ft\\ \\ Second \space distance \\ Distance, s= v*t=30*120= 3600 ft\\ Third \space distance \\ v=u+at \\ 0=30+a*15\\ a=2ft/s^2\\ Distance, v^2=u^2+2ast\\ 0=900-2*2*s \implies s= 225 ft\\ Total = 450+3600+225=4275ft=1303.02 m$