Question

A block project up an inclined plane at 20 degrees with horizontal and the block has 

an initial velocity of 6 m/s. If the coefficient of kinetic friction is 0.25, how far will the 

block go up the plane?

Answer 1

$Work done =Force X Distance$

Force=uN=umg cosA

U-coefficient of friction

N-Mg cosA ,normal force exerted by inclined plane on the object on the inclined plane.

A-is the inclined angle

Let's assume mg=20

$Work done =(umg cosA + mg sine A)$

Force=0.25 cos 20

F=0.114268N

Work done =(0.25 X 20 X cos 20) + (20 sin 20)

Work done =222.308J

222.308J=0.1143N X d

Distance =1944.95m