Question #205306

The ball of a float has a diameter of 4-in, and the thickness of the metal is 0.05 in. How much does it weigh if it is made of copper? (Copper weighs 556 lb. per cu. ft.)



1
Expert's answer
2021-06-11T06:10:48-0400

Volume of the entire ball=43π3= \frac{4}{3} \pi ^3

Volume =4322723=\frac{4}3*\frac{22}7*2^3

Volume =33.524in3=33.524 in^3

The volume of the hollow area of the ball =43π3=\frac{4}3 \pi^3

V=43227[20.05]3=\frac{4}3*\frac{22}7*[2-0.05]^3

V=31.0719in3V=31.0719 in^3

Volume of copper =33.52431.072=33.524-31.072

Vof copper=2.452in3V of \space copper =2.452in^3

Density of Cu=0.324lb/in3=0.324 lb/in^3

Mass of Cu=Density of CuVolume of Cu=Density \space of \space Cu*Volume \space of \space Cu

Mass of Cu=0.3242.452=0.324*2.452

Mass of Cu=0.794lb=0.794 lb

Weight of copper =0.7942.20410=0.794 *2.204*10

Weight of copper=17.510kg=17.510kg


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