Question #205306

The ball of a float has a diameter of 4-in, and the thickness of the metal is 0.05 in. How much does it weigh if it is made of copper? (Copper weighs 556 lb. per cu. ft.)



Expert's answer

Volume of the entire ball=43π3= \frac{4}{3} \pi ^3

Volume =43∗227∗23=\frac{4}3*\frac{22}7*2^3

Volume =33.524in3=33.524 in^3

The volume of the hollow area of the ball =43π3=\frac{4}3 \pi^3

V=43∗227∗[2−0.05]3=\frac{4}3*\frac{22}7*[2-0.05]^3

V=31.0719in3V=31.0719 in^3

Volume of copper =33.524−31.072=33.524-31.072

Vof copper=2.452in3V of \space copper =2.452in^3

Density of Cu=0.324lb/in3=0.324 lb/in^3

Mass of Cu=Density of Cu∗Volume of Cu=Density \space of \space Cu*Volume \space of \space Cu

Mass of Cu=0.324∗2.452=0.324*2.452

Mass of Cu=0.794lb=0.794 lb

Weight of copper =0.794∗2.204∗10=0.794 *2.204*10

Weight of copper=17.510kg=17.510kg


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