Question

 2° chord basis curve is to connect two tangent lines whose bearing are N32°15'18"E and N54°56'18"E. PC is contained in the first tangent line. Determine, the bearing of a radius whose end point is PT.

Answer 1

The radial bearing from tangent line is a perpendicular bearing.

Given data,

Approach Bearing = N32^o15'18''E

Exit bearing = N54^o56'18''E

Therefore, the bearing of radius at PT is: $90^0-N54^056'18''E=S35^003'42''E$